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The ratio of magnetic potentials due to magnetic dipole in the end-on position to that in the broad side on position for the same distance from it is - |
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Answer» Solution :V=(KMcostheta)/(R^(2)),V_("axis")=(KM)/(r^(2))becausetheta=0` `V_("equator")=0becausetheta=90^(@)RARR(V_("axis"))/(V_("equator"))=oo` |
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