1.

The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1:4. the ratio of number of their molecules is:

Answer»

`1:8`
`3:16`
`1:4`
`7:32`

SOLUTION :Ratio of number of MOLECULES =Ratio of number of MOLES
`=n_(O_(2)):n_(H_(2))`
`=((w)/(m))_(O_(2)):((w)/(m))_(N_(2))`
`=(1)/(32):(4)/(28)=7:32`


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