1.

The ratio of minimum wavelengths of Lyman and Balmer series will be

Answer»

1.25
0.25
5
10

Solution :For minimum wavelength, `lambda ALPHA n^(2)`
`lambda_("LYMAN")/lambda_("BALMER")=(1/2)^(2)`
`lambda_(L)/(lambda_(B))=1/4 =0.25`


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