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InterviewSolution
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The ratio of minimum wavelengths of Lyman &Balmer series will be :-50.(2) 0.25(4) 10(3) 5 |
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Answer» 2. 0.25Lyman series of the hydrogen spectrum can be represented by the equation: v=3.2881 x10^15 s^-1(1/1^2-1/n^2) (where n=2,3,...)1/wavelength = R*(1-1/n^2), where R is the Rydberg constant for hydrogen = 1.0974 x 10^7 m^-1. Since we're looking at 1/wavelength, the minimum wavelength will occur when 1/wavelength is a maximum, which happens when n goes to infinity (thus 1/n^2 goes to 0), and 1/wavelength = R. Thus, the minimum wavelength is 1/R = 91.12 nmBalmer's original formula was Wavelength = 3645.6 . 10^–10 ( n^2 / (n^2 – 4) ) When n => infinity Wavelength = 3.6456 . 10^–7 m ( or 364.5 nm)Ratio will be 91.2/364.5=0.25 |
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