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The ratio of moment of an electron and an `alpha`-particle which are accelerated from rest by a potential difference of `100V` isA. 1B. `sqrt((2m_(2))/(malpha))`C. `sqrt((m_(e))/(malpha))`D. `sqrt((m_(e))/(2m_(alpha))` |
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Answer» Correct Answer - D Momentum `p=mvand v=sqrt((2qV)/(m))` `p=sqrt(2qmV)` `p=sqrt(qm)` `(p_(e))/(p_(alpha))=sqrt((em_(e))/(2em_(alpha)))` `therefore (p_(e))/(p_(alpha))=sqrt((m_(e))/(2malpha))` |
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