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The ratio of momenta of an electron and an alpha particle which are accelerated from rest through a potential difference of 100 volts is : |
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Answer» <P>1 `U=(P^(2))/(2m)` (p is momentum) `:.(p_(e)^(2))/(2m_(e))=q_(e)V""....(1)` ` and (p_(alpha)^(2))/(2m_(alpha))=q_(alpha)V ""....(2)` DIVIDING we get `((P_(e))/(P_(alpha)))^(2)((m_(alpha))/(m_(e)))=(q_(e))/(q_(alpha))` `:.(p_(e))/(p_(alpha))= sqrt((q_(e))/(q_(alpha))*(m_(e))/(m_(alpha)))` `:. (q_(e))/(p_(alpha))=(1)/(2)` `:. (P_(e))/(P_(alpha))= sqrt((m_(e))/(2m_(alpha)))` |
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