The ratio of number of electrons present I four shells of an element is1 : 4 : 4 : 1, fourth shellis the valence shell . Thenmassof total positive charge present in the atom is ____________ times to that of mass of electron

The ratio of number of electrons present I four shells of an element i

1.	The ratio of number of electrons present I four shells of an element is1 : 4 : 4 : 1, fourth shellis the valence shell . Thenmassof total positive charge present in the atom is ____________ times to that of mass of electron
Answer» 36 , 704 27 , 555 18 , 370 55, 110 Solution :Theelectronic configuration of the ELEMENT is `{:(K,L,M,N),(2,8,8,2):}` THEREFORE the atomic number is 20 . We know that mass of PROTON is 1837 TIMES that of electron, therefore total positive charge present is `20x1837 =36740`,