InterviewSolution
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InterviewSolution
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The ratio of pressure of the same gas in two containers in `(n_(1) T_(1))/(n_(2) T_(2))` where `n_(1)` & `n_(2)` are the number of moles and `T_(1)` & `T_(2)` are respective temperatures. If the containers are now joined find the ratio of pressure to the pressure :A. `(P_(1) T_(2) + P_(2) T_(1))/(2 T_(1) T_(2))`B. `(P_(1) T_(1) + P_(2) T_(1))/(T_(1) T_(2))`C. `(P_(1) T_(1) + P_(2) T_(2))/(2 T_(1) T_(2))`D. none of these |
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Answer» Correct Answer - A a. Given `(P_(1))/(P_(2)) = (n_(1) T_(2))/(n_(2) T_(2))` `P prop nT`. It implies that volume of both containers is same. After mixing. `P (2V) = (n_(1) + n_(2)) RT = ((P_(1) V)/(RT_(1)) + (P_(2) V)/(RT_(2))) RT` `P//T = (1)/(2) ((P_(1))/(T_(1)) + (P_(2))/(T_(2))) = (1)/(2) ((P_(1) T_(2) + P_(2) T_(2))/(T_(1) T_(2)))` |
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