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The ratio of r.m.s. value of an A.C. voltage and its mean value over half cycle is ....

Answer»

`SQRT2:1`
`sqrt2:pi`
`2:pi`
`pi:2SQRT2`

SOLUTION :Mean VALUE over half cycle of A.C. voltage
`=(2V_0)/pi` and r.m.s. value `=V_0/sqrt2`
`therefore` Ratio = `(ltVgt)/V_"rms" = (2V_0)/pixxsqrt2/V_0 =(2sqrt2)/pi`


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