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The ratio of r.m.s. value of an A.C. voltage and its mean value over half cycle is .... |
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Answer» `SQRT2:1` `=(2V_0)/pi` and r.m.s. value `=V_0/sqrt2` `therefore` Ratio = `(ltVgt)/V_"rms" = (2V_0)/pixxsqrt2/V_0 =(2sqrt2)/pi` |
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