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The ratio of the area of triangle inscribed inellipse `(x^2)/(a^2)+(y^2)/(b^2)=1`to that of triangle formed by the corresponding points onthe auxiliary circle is 0.5. Then, find the eccentricity of the ellipse. |
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Answer» The given ratio is `(b)/(a)=(1)/(2)` Now, `e^(2)=1-(b^(2))/(a^(2))=1-(1)/(4)=(3)/(4)or e=(sqrt(3))/(2)` |
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