Saved Bookmarks
| 1. |
The ratio of the difference in energy between the first and the second Bohr orbit to that between the second and the third Bohr orbit is |
|
Answer» Solution :`E_(1)-E_(2)=1312/(L^(2))=1312/(2^(2))=1312(3/4)` `E_(2)-E_(3)=1312/(2^(2))=1312/(3^(2))=1312(5/36)` `therefore(E_(1)-E_(2)):(E_(2)-E_(3))=3/4:5/36=27:5` |
|