1.

The ratio of the largest to shortest wavelength in Balmer series of hydrogen spectra is,A. `25/9`B. `17/6`C. `9/5`D. `5/4`

Answer» Correct Answer - C
`1/lambda_(max)=RZ^(2)(1/n_(1)^(2)-1/n^(2_2))` where `n_(1)=2,n-(2)=3`
` 1/lambda_(min)=RZ^(2)(1/n_(1)^(2)-1/n^(2_(2)) Where n_(1)=2,n_(2)=a`
` 1/lambda_(min)=RZ^(2)(1/n_(1^(2))-1/2^(2_(2)))` where `n_(1)=2,n_(2)=a`


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