1.

The ratio of the number of moles of a monoatomic to a polyatomic gas in a mixture of the two, behaving as an diatomic gas is : (vibrational modes of freedom is to be ignored)A. `2:1`B. `1:2`C. `2:3`D. `3:2`

Answer» Correct Answer - B
Let the required ratio be `n:1`
`Q_(1) = n((f_(1)R)/(2)) Delta T` and `Q_(2) = 1((f_(3)R)/(2)) Delta T`
`and Q = (n+1)((f_(2)R Delta T)/(2))`
`Q = Q_(1)+Q_(2)`, so `(n+1)f_(2)=nf_(1)+f_(3)`
or, `(n+1)5=n(3)+6impliesn=1//2`.


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