InterviewSolution
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InterviewSolution
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The ratio of the range of the particle and its maximum range in the inclined plane is:A. `1:2`B. `1:sqrt(2)`C. `1:sqrt(3)`D. `1:1` |
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Answer» Correct Answer - d `R=v_(0)cos 30^(@) T-1/2g sin 30^(@) T^(2)` `=10 (sqrt(3))/2-2/(sqrt(3))-1/2xx10xx1/2(2/(sqrt(3)))^(2)=20/3` `R_(max)=(v_(0)^(2))/(g(1+sin theta_(0)))` `=(10^(2))/(10(1+sin theta_(0)))` `=(10^(2))/(10(1+sin 30^(@)))=20/3` So, `R/(R_(max))=1` |
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