1.

The ratio of the reading of 2 watt-meters connected to measure power in a balanced 3-phase load is 2: 1 and the load is inductive. The power factor of load is?(a) 0.866 lag(b) 0.615 lead(c) 0.866 lead(d) 0.625 lagThe question was asked by my college professor while I was bunking the class.I'm obligated to ask this question of Advanced Problems on Measurement of Power in Polyphase Circuit topic in chapter Measurement of Power and Related Parameters of Electrical Measurements

Answer»

Correct choice is (a) 0.866 LAG

Easy explanation: Power factor, cosθ = COS arc tan (3)^0.5 \(\FRAC{W_1-W_2}{W_1+W_2}\)

Since, \(\frac{W_1}{W_2} = \frac{2}{1}\)

So, power factor = cos arc tan (3)^0.5 \(\frac{2-1}{2+1}\)

= cos 30° = 0.866 lag.



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