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The ratio of the speed of the electron in the first Bohr orbit of hydrogen and the speed of light is equal to (where `e, h` and `c` have their usual meanings)A. `2pihc//e^(2)`B. `e^(2)h//2pic`C. `e^(2)c//2pih`D. `2pie^(2)//hc` |
Answer» Correct Answer - D Speed of electron in nth orbit `("in" CGS) v_(n) = (2piZe^(2))/(nh) (k = 1)` For first orbit `H_(2) , n = 1` and `Z = 1` So `v = (2pie^(2))/(h) rArr (v)/(c ) = (2pie^(2))/(hc)` |
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