1.

The ratio of the speed of the electrons in the ground state of hydrogen to the speed of light in vacuum isA. `1//2`B. `2//137`C. `1//137`D. `1//237`

Answer» Correct Answer - C
Speed of electron in nth orbit of hydrogen atom
`v = (e^(2))/(2 epsilon_(0)nh)`
In ground state `n = 1 rArr v = (e^(2))/(2 epsilon_(0) nh)`
`rArr (v)/(c ) = (e^(2))/(2 epsilon_(0) nh)`
`= ((1,6 xx 10^(-19))^(2))/(2 xx 8.85 xx 10^(-12) xx 3xx 10^(3) xx 6.6 xx 10^(-34))`
`= (1)/(137)`


Discussion

No Comment Found

Related InterviewSolutions