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The ratio of the speed of the electrons in the ground state of hydrogen to the speed of light in vacuum isA. `1//2`B. `2//137`C. `1//137`D. `1//237` |
Answer» Correct Answer - C Speed of electron in nth orbit of hydrogen atom `v = (e^(2))/(2 epsilon_(0)nh)` In ground state `n = 1 rArr v = (e^(2))/(2 epsilon_(0) nh)` `rArr (v)/(c ) = (e^(2))/(2 epsilon_(0) nh)` `= ((1,6 xx 10^(-19))^(2))/(2 xx 8.85 xx 10^(-12) xx 3xx 10^(3) xx 6.6 xx 10^(-34))` `= (1)/(137)` |
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