1.

The ratio of the wavelength for the transition from n = 2 to n = 1 in Li^(++).He^(+) and H is

Answer»

`1 : 2 : 3`
`1 : 4:9`
`3 : 2 : 1`
`4 : 9 : 36`

SOLUTION :According to RYDBERG FORMULA, the WAVELENGTH
`1/lambda=Z^2R (1/n_1^2-1/n_2^2)`For, `Li^(+ +), z = 3`
`lambda prop 1/z^2``He^(+),z= 2`
`lambda_(He^(+)) : lambda_(He^(+)) : lambda_(H) = 4 : 9 : 36`H, Z = 1


Discussion

No Comment Found

Related InterviewSolutions