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The ratio of wavelength of the last line of Balmer series and the last line of Lyman series is .... |
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Answer» `1:1` `(1)/(lambda_(B))=R[(1)/(2^(2))-(1)/(OO^(2))]` For LAS line `n=oo` `:.(1)/(lambda_(B))=(R)/(4)....(1) [ :. (1)/(2^(2))-(1)/(oo^(2))]` For Lyman series, `(1)/(lambda_(L))=R[(1)/(1^(2))-(1)/(oo^(2))]` For las line `n=oo` `:.(1)/(lambda_(L))=R....(2)` `:.` Taking ratio of equation (2) and (1) `lambda_(B)=Rxx(4)/(R)-4` `:. lambda_(B) :. lambda_(B)=4:1` |
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