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The rationalising factor of \(\frac{1}{\sqrt{27}}\) is A) 9 B) \(\sqrt{6}\)C) \(\sqrt{3}\) D) 3 

Answer»

Correct option is (C) \(\sqrt{3}\)

\(\because\) \(\frac{1}{\sqrt{27}}\times\sqrt3\) \(=\frac{\sqrt3}{3\sqrt{3}}\) \(=\frac13\) which is an irrational number.

\(\therefore\) \(\sqrt{3}\) is the rationalising factor of \(\frac{1}{\sqrt{27}}.\)

Correct option is  C) \(\sqrt{3}\) 



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