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The reactance of a capacitor of 1/pi in areA.C. circuit having frequency of 50Hz is .....

Answer»

`100Omega`
`10 OMEGA`
`50 Omega`
`10^(-2) Omega`

Solution :f=50 HZ, `C=1/piF`
`therefore X_C=1/(OMEGAC)=1/(2pifC)=1/(2pixx50xx1/pi)=1/100`
`therefore X_C=10^(-2) Omega`


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