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The reaction `2A_((g))+B_((g))hArr3C_((g))+D_((g))` is begun with the concentrations of A and B both at an initial value of `1.00` M. when equilibrium is reached, the concentration of D is measured and found to be `0.25` M. The value for the equilibrium constant for this reaction is given by the expressionA. `"["(0.75)^(3)(0.25)"]"div"["(1.00)^(2)(1.00)"]"`B. `"["(0.75)^(3)(0.25)"]"div"["(0.50)^(2)(0.75)"]"`C. `"["(0.75)^(3)(0.25)"]"div"["(0.50)^(2)(0.25)"]"`D. `"["(0.75)^(3)(0.25)"]"div"["(0.75)^(2)(0.25)"]"` |
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Answer» Correct Answer - B `2A+BhArr3C+D` `{:("Initial",1,1,0,0),(Eq.,1-0.50,1-0.25,0.75,0.25):}` `K=((0.75)^(3)(0.25))/((0.50)^(2)(0.75))` |
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