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The reaction 2H2(g) + 2NO(g) → 2H2O(g) + N2(g) is first order in H2 and second order in NO. The rate constant of the reaction at a certain temperature is 0.42M-2s-1. Calculate the rate when [H2] = 0.015 M and [NO] = 0.025 M. |
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Answer» Given, 2H2(g) + 2NO(g) → 2H2O(g) + N2(g) Order of reaction in H2 = \(n_{H_1}\) = 1 Order of reaction in NO = nNO = 2 Rate constant = k = 0.42 M-2s-1 [H2] = 0.015 M; [NO] = 0.025 M Rate of reaction = R = ? By rate law, Rate = R = k [H2] [NO]2 = 0.42 x 0.015 x (0.025)2 M-2s-1 = 3.94 x 10-6 Ms-1 ∴ Rate of reaction = R = 3.94 x 10-6 Ms-1 |
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