1.

The reaction at anode in NICAD cell is

Answer»

`NiO_(2) + 2 OH^(-) to Ni(OH)_(2) + 2e^(-) + H_(2)O`
`Cd to Cd^(2+) + 2e^(-)`
`Cd + 2OH^(-) to Cd (OH)_(2) + 2e^(-)`
`Ni to Ni^(2+)+ 2e^(-)`

Solution :At anode in NICAD CELL, REACTION is `Cd to Cd^(2+)+ 2e^(-)`


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