1.

The reaction CH_3OC_2H_5 with cold HI gives

Answer»

`CH_3OH+C_2H_5I`
`CH_3I+ C_2H_5OH`
`CH_3I + C_2H_5I`
`CH_3OH + C_2H_5OH`

Solution :`CH_3OC_2H_5+HI OVERSET("COLD")to CH_3I+C_2H_5OH`
The NUCLEOPHILE `I^-` attacks `-CH_3` group and not `-CH_2` group of ethyl group , because the POSITIVE CHARGE on `-CH_2` is reduced by electron -donating effect of `-CH_3` in ethyl is more than on `-CH_2` of ethyl group .


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