1.

The reaction,CHCl3(g) + Cl2(g) → CCl4(g) + HCl(g) is first order in CHCl3 and 1/2 order in Cl2. Write the rate law and overall order of reaction.

Answer»

Since the reaction is first order in CHCl3 and 1/2 order in Cl2, the rate law for the reaction will be, Rate = k[CHCl3] × [Cl2]1/2

The overall order (n) of the reaction will be, n \(= l + = \frac{1}{2} = \frac{3}{2}.\)



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