The reaction of cynamide, `NH_(2)CN(s)`, with dioxygen was carried out in a bomb calorimeter, and `DeltaU` was found to be `- 742.7 k J mol^(-1)` at 298 K. Calculate the enthalpy change of the reaction at 298 K `NH_(2)CN(s) + (3)/(2)O_(2)(g)rarrN_(2)(g)+CO_(2)(g) +H_(2)O(l)`

The reaction of cynamide, `NH_(2)CN(s)`, with dioxygen was carried out

1.	The reaction of cynamide, `NH_(2)CN(s)`, with dioxygen was carried out in a bomb calorimeter, and `DeltaU` was found to be `- 742.7 k J mol^(-1)` at 298 K. Calculate the enthalpy change of the reaction at 298 K `NH_(2)CN(s) + (3)/(2)O_(2)(g)rarrN_(2)(g)+CO_(2)(g) +H_(2)O(l)`
Answer» `Deltan_(g)=(n_(p) -n_(p))_(g)= 2-(3)/(2) = +(1)/(2)` mol `DeltaH =DeltaU +Deltan_(g) RT = - 742.7 kJ mol^(-1) +(+(1)/(2)mol)(8.314xx10^(-3)kJ K^(-1) mol^(-1))(298K) ` `= - 742.7 +1.2kJ mol^(-1) = - 741.5 kJ mol^(-1)`

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The reaction of cynamide, `NH_(2)CN(s)`, with dioxygen was carried out in a bomb calorimeter, and `DeltaU` was found to be `- 742.7 k J mol^(-1)` at 298 K. Calculate the enthalpy change of the reaction at 298 K `NH_(2)CN(s) + (3)/(2)O_(2)(g)rarrN_(2)(g)+CO_(2)(g) +H_(2)O(l)`

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