The reaction quotient (Q) for the reaction `N_(2)(g) + 3H_(2)(g)hArr2NH_(2)(g)` is given by Q `= ([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))`. The reaction will proceed towards right side if where `K_(c)` is the equilibrium constant.A. `Q gt K_(c)`B. `Q = 0`C. `Q = K_(c)`D. `Q lt K_(c)`

The reaction quotient (Q) for the reaction `N_(2)(g) + 3H_(2)(g)hArr2N

1.	The reaction quotient (Q) for the reaction `N_(2)(g) + 3H_(2)(g)hArr2NH_(2)(g)` is given by Q `= ([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))`. The reaction will proceed towards right side if where `K_(c)` is the equilibrium constant.A. `Q gt K_(c)`B. `Q = 0`C. `Q = K_(c)`D. `Q lt K_(c)`
Answer» Correct Answer - A `N_(2)(g) + 3H_(2)(g)hArr2NH_(3)(g)` `.:` (Quotient) `=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))` , `Delta n = 2-4 = -2` At equilibrium Q is equal to `K_(c)` but for the progress of reaction towards right side `Q gt K_(c)` .

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The reaction quotient (Q) for the reaction `N_(2)(g) + 3H_(2)(g)hArr2NH_(2)(g)` is given by Q `= ([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))`. The reaction will proceed towards right side if where `K_(c)` is the equilibrium constant.A. `Q gt K_(c)`B. `Q = 0`C. `Q = K_(c)`D. `Q lt K_(c)`

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