The reaction quotient (Q) for the reaction `N_(2)(g) + 3H_(2)(g)hArr2NH_(3)(g)` is given by Q `= ([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))`. The reaction will proceed towards right side if where `K_(c)` is the equilibrium constant.A. (A) `Q=K_(C)`B. (B) `QltK_(C)`C. (C) `QgtK_(C)`D. (D) `Q=0`

The reaction quotient (Q) for the reaction `N_(2)(g) + 3H_(2)(g)hArr2N

1.	The reaction quotient (Q) for the reaction `N_(2)(g) + 3H_(2)(g)hArr2NH_(3)(g)` is given by Q `= ([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))`. The reaction will proceed towards right side if where `K_(c)` is the equilibrium constant.A. (A) `Q=K_(C)`B. (B) `QltK_(C)`C. (C) `QgtK_(C)`D. (D) `Q=0`
Answer» Correct Answer - C When`QgtK`, reaction will favour backward direction and when`QltK`, it will favour forward direction

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The reaction quotient (Q) for the reaction `N_(2)(g) + 3H_(2)(g)hArr2NH_(3)(g)` is given by Q `= ([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))`. The reaction will proceed towards right side if where `K_(c)` is the equilibrium constant.A. (A) `Q=K_(C)`B. (B) `QltK_(C)`C. (C) `QgtK_(C)`D. (D) `Q=0`

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