InterviewSolution
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The reading of ammeter in the adjoining diagram will be |
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Answer» `(2)/(17)A` `I-I_(1)3V,3Omega` `Ixx2-2+21+Ixx1+2I_(1)=0` `3I+_2I_(1)=2""(1)` `-1-(I-I_(1))xx4+3+2I_(1)=0` `-4I+4I_(1)+2+2I_(1)=0` `-41+61^(1)=-1` `6I+4I_(1)=4""...(2)` `-6I+9I_(1)=-3""...(1)` `13I_(1)=1""thereforeI_(1)=1//13A""...(2)` |
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