1.

The reading of ammeter in the adjoining diagram will be

Answer»

`(2)/(17)A`
`(3)/(11)A`
`(1)/(13)A`
`(4)/(15)A`

Solution :`2V, 2OMEGA`

`I-I_(1)3V,3Omega`
`Ixx2-2+21+Ixx1+2I_(1)=0`
`3I+_2I_(1)=2""(1)`
`-1-(I-I_(1))xx4+3+2I_(1)=0`
`-4I+4I_(1)+2+2I_(1)=0`
`-41+61^(1)=-1`
`6I+4I_(1)=4""...(2)`
`-6I+9I_(1)=-3""...(1)`
`13I_(1)=1""thereforeI_(1)=1//13A""...(2)`


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