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The reading on a high resistance voltmeter, when a cell is connected across it, is 2.2 V. When a 5 Omegaresistance is connected across the terminals of the cell in parallel with the voltmeter, the reading is 1.8 V. Determine the internal resistance of the cell. |
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Answer» Solution :Here reading of voltmeter when connected directly to a cell = emf of cell `epsi` =2.2 V. External resistance R=5`OMEGA`and terminal voltage V = 1.8 V. ` therefore `Internal resistance of cell `r = (epsi - V)/(V) .R = (2.2 - 1.8)/(1.8) xx 5 = 1.1 Omega` |
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