1.

The real angle of dip if a magnet is suspended at an angle of 30^(@)needle makes and angle of 45^(@)with horizontal is

Answer»

`tan^(-1)sqr(3)/(2)`
`tan^(-1)SQRT(3)`
`tan^(-1)sqrt(3)/(2)`
`tan^(-1)(2)/sqrt(3)`

Solution :`because tan delta=(V)/(H)`
`tan 45^(@)=(v)/(H cos 30^(@))`
`delta^(-1)sqrt(3)/(2)`


Discussion

No Comment Found

Related InterviewSolutions