1.

The rectangular coil is moving-coil galvanometer has 100 turns, each of length 5 cm and breadth 3 cm, and is suspended in a radial magnetic field of intuction 0.05 Wb//m^(2). The twist constant of the suspension fibre is 2 xx 10^(-9) N.m/degree. Calculate the deflecting torque and the current through the coil which will deflect it through 30^(@).

Answer»

Solution :Data: `N=100, A=lb =5 cm xx 3cm = 15 cm^(2) = 15 xx 10^(-4) m^(2)`,
`B=0.05 Wb//m^(2), C=2 xx 10^(-9) N.m//"DEGREE", theta=30^(@)`
`tau_(p) = tau_(R)therefore NIAB=Ctheta`
`therefore` The current through the coil, `I=(Ctheta)/(NAB)`
`=(6 xx 10^(-8))/(100 xx 15 xx 10^(-4) xx 0.05) = (600 xx 10^(-10))/(15 xx 5 xx 10^(-4)) = 8 xx 10^(-6)` A


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