1.

The reduction potential of hydrogen half cell will be negative if:

Answer»

`p(H_(2))=1ATM and [H^(+)]=1.0M`
`p(H_(2))=2ATM and [H^(+)]=1.0M`
`p(H_(2))=2atm and [H^(+)]=2.0M`
`p(H_(2))=1atm and [H^(+)]=2.0M`

SOLUTION :For hydrogen ELECTRODE
`H^(+)(aq)+e^(-)to(1)/(2)H_(2)(g)`
`E=E^(@)-(0.0591)/(1)"log"((p_(H_(2)))^(1//2))/([H^(+)])`
`=-0.0591"log"((p_(H_(2)))^(1//2))/([H^(+)])""(becauseE^(@)=0)`
E will be -ve when `((p_(H_(2)))^(1//2))/([H^(+)])` is +ve,
i.e., `(p_(H_(2)))^(1//2)gt[H^(+)]` which is so in case of (b).


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