1.

The refracting angle of a prism is A and refrac tive index of the material of the prism is cot(A/2) The angle of minimum deviation is :

Answer»

`pi-A`
`pi-2A`
`pi-A/2`
`pi-4A`

Solution :`ETA=(SIN((A+delta_m)/(2)))/(sin""A/2)`
`THEREFORE COT A/2=(sin((A+delta_m)/(2)))/(sin""A/2)`
`therefore(cos A//2)/(sin A//2)=(sin((A+delta_m)/(2)))/(sin""A/2)`
`therefore sin(9^@-A/2)=sin((A+delta_m)/(2))`
`therefore (180^@-A)/(2)=(A+delta_m)/(2)`
`therefore 180^@-A=A+delta_m`
`therefore delta_m=180^@-2A` or `delta_m=pi-2A`


Discussion

No Comment Found

Related InterviewSolutions