InterviewSolution
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InterviewSolution
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The refracting angle of a prism is `A` and refractive index of the material of the prism is `cos(A//2)`. The angle of minimum deviation isA. `180^(@)-3A`B. `180^(@)-2A`C. `90^(@)-A`D. `180^(@)+2A` |
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Answer» Correct Answer - B The refractive index of the material of the prism `mu=(sin .(A+delta_(m))/(2))/(sin .(A)/(2))` `impliescot.(A)/(2)=((sin(A+delta_(m)))/(2))/(sin .(A)/(2))` `sin((A+delta_(m))/(2))=cot.(A)/(2)sin .(A)/(2)` `sin ((A+delta_(m))/(2))=(cos.(A)/(2))/(sin .(A)/(2))sin .(A)/(2)` `sin ((A+delta_(m))/(2))=sin ((pi)/(2)-(A)/(2))` `implies(A+delta_(m))/(2)=(pi)/(2)-(A)/(2)` `A+delta_(m)=pi -Aimpliesdelta_(m)=180-2A` |
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