1.

The refracting angle of a prism is A and the refractive index is cot (A//2). The angle of minimum deviation is :

Answer»

`180^(@) - 2A`
`180^(@) - A`
`180^(@) - 3A`
`180^(@) - 4A`.

Solution :(a) `mu=sin((A+delta_(m))/(2))/(sin""(A)/(2))`
Given `"" mu = cot (A)/(2)`
`therefore cot""(A)/(2)=sin(A+(delta_(m))/(2))/(sin((A)/(2)))`
`rArr "" COS((A)/(2))=sin((A+delta_(m))/(2))`
`rArrsin(90^(@)-(A)/(2))=sin""((A+delta_(m))/(2))`
`rArr "" 90^(@)-(A)/(2)=(A+delta_(m))/(2)`
`sin = 180^(@) - 2A`.


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