1.

The refractive index of a material of a plane-concave lens is 5//3 the radius of curvature is 0.3m. The focal length of the lens in air is

Answer»

`-0.45m`
`-0.6m`
`-0.75m`
`-1.0m`

Solution :(a) LENS MAKER's formual `1/f=(mu-1)[1/(R_(1))-1/(R_(2))]`
where `R_(2)=OO,R_(1)=0.3m`
`:. 1/f=(5/3-4)(1/0.3-1/(oo))`
`implies1/f=2/3xx1/0.3`
or `f=0.45m`


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