1.

The region inside a current carrying torodial winding is filled with tungsten of susceptibility 6.8 xx 10^(-5). What is the percentage increase in the magnetic field in the presence of the material with respect to the magnetic field without it ?

Answer»

Solution :The magnetic field in the current carrying torodial WINDING without TUNGSTEN is
`B= muH`
`THEREFORE (B- B_0)/( B_0) = (MU-mu_(0 ) )/( mu_(0) ) ""…(1)`
But `mu= mu_(0)(1+ chi_(m) ) `
`therefore (mu)/( mu_0) = 1+ chi_(m) `
`therefore (mu)/( mu_0) -1 = chi_(m)`
`therefore (mu- mu_0)/( mu_0) = chi_m`
`therefore` Using this equation,
`(B- B_0)/( B_0) = chi_m`
`therefore` Percentage increase in the magnetic field in presence of tungsten is
`(B- B_0)/( B_0) xx 100 = (6.8 xx 10^(-5) )xx 100`
`= 6.8 xx 10^(-3)`%


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