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The relation between force `F` and density `d` is `F=(x)/(sqrt(d))`. The dimension of `x` isA. `["L"^(-1//2)"M"^(3//2)"T"^(-2)]`B. `["L"^(-1//2)"M"^(1//2)"T"^(-2)]`C. `["L"^(-1)"M"^(3//2)"T"^(-2)]`D. `["L"^(-1)"M"^(1//2)"T"^(-2)]` |
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Answer» Correct Answer - A Subsituting dimensions, `["MLT"^(-2)]=(x)/(sqrt(["ML"^(-3)]))` `rArr" "x=["M"^(3//2)"L"^(-1//2)"T"^(-2)]` |
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