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The relation between `K_(p)` and `K_(c)` is `K_(p)=K_(c)(RT)^(Deltan)` unit of `K_(p)=(atm)^(Deltan)`, unit of `K_(c)=(mol L^(-1))^(Deltan)` Consider the two reaction: `XeF_(6)(g)+H_(2)O(g) hArr XeO_(3)F_(4)(g)+2HF(g), K_(1)` `XeO_(4)(g)+XeF_(6)(g) hArr XeOF_(4)(g)+XeO_(3)F_(2)(g), K_(2)` Then the equilibrium constant for the following reaction `XeO_(4)(g)+2HF(g) hArr XeO_(3)F_(2)(g)` is given by:A. `K_(1)//K_(2)^(2)`B. `(K_(1)//K_(2))^(1//2)`C. `K_(1)^(2)//K_(2)^(3)`D. `K_(2)//K_(1)` |
Answer» Correct Answer - D `K=K_(2)/K_(1)` |
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