1.

The relation between the circumference of an electron orbit in a hydrogen atom and the de Broglie wavelength of the electron in the same orbit is given by

Answer»

`2 pi R=n lambda`
`2 pi r = nh//2`
`2 pi r = 2 n lambda`
`2 pi r = n lambda //4`

Solution :`lambda=h/(mv)=(HR)/(mvr)=(hr)/((nh)/(2PI))`
`lambda=(2pi r)/n`
`:. n lambda =2 pi lambda`
`lambda=2 pi r""(n=1)`


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