1.

The relation between the phase of current and voltage in a circuit containing only inductor is ….

Answer»

VOLTAGE leads ahead by `PI/2`
current leads ahead by `pi/2`
both are in same phase
phase DIFFERENCE is `pi`

Solution :The current in a circuit containing only INDUCTOR is `I=(V_m cos (omegat-pi/2))/(omegaL)`, hence current lags behind the voltage by `pi/2` phase. So voltage leads ahead by `pi/2`


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