1.

The relation between time and displacement is t=alphax^(2)+betax where alpha and beta are constants. What is retardation of the body:

Answer»

`2alphav^(3)`
`2alphav^(2)`
`2ALPHA^(2)v^(2)`
`2alphabetav`

Solution :`t=alphax^(2)+betax`
Differentiating both sides w.r.t . Time,
`1=2alphax.(dx)/(dt)+beta(dx)/(dt) 1=2alphaxv +betav`
`1=(2alphax+beta)v impliesv=(1)/(2alpha+beta)`
Differentiating equation (i)w.r.t. time again
`0=2alphax.(dv)/(dx)+2alphav.(dv)/(dt)+beta(dv)/(dt)`
or `0=2alphaxa+2alphav^(2)+betaa`
`0=(1alphax +beta)a+2alphav^(2)`
`a= -((2alphav^(2))/(2alphax+beta))`
Using equation (ii)
`a= - 2alphav^(3)`
THUS retardation=2 `alphav^(3)`


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