1.

The relationship between equivalent conductivity (lambda), specific conductivity (K) and normality (xN) of a solution is

Answer»

`K=(1000xx X)/(lambda)`
`lambda=(1000xx K)/(x)`
`lambda=(K)/(1000 xx x)`
`K=(lambda)/(1000 xx x)`

SOLUTION :`lambda=(1000K)/(c)=(1000xx0.024)/(0.12)=200`


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