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InterviewSolution
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The relationship between the dissociation energy of `N_2` and `N_2^+` isA. dissociation energy of `N_2^+` gt dissociation energy of `N_2`B. dissociation energy of `N_2` = dissociation energy of `N_2^+`C. dissociation energy of `N_2` gt dissociation energy of `N_2^+`D. dissociation energy of `N_2`can either be lower or higher than the dissociation energy of `N_2^+` |
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Answer» Correct Answer - C The dissociation energy will be more when the bond order will be greater and bond order `prop` dissociation energy Molecular orbital configuration of `N_2(14)=sigma1s^2 , overset***sigma1s^2, sigma2s^2 , overset***sigma2s^2, sigma2p_y^2~~ pi2p_z^2,pi2p_x^2` So, bond order of `N_2=(N_b-N_a)/2=(10-4)/2=3` and bond order of `N_2^(+)=(9-4)/2=2.5` As the bond order of `N_2` is greater than `N_2^+` so , the dissociation energy of `N_2` will be greater than `N_2^+` |
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