The relative density of a material of a body is found by weighing it first in air and then in water. If the wt. of the body in air is W_(1)=8*00+-0*05newton and weight in water is W_(2)=6*00+-0*05 newton. Then the relative density, p_(r)=(W_(1))/(W_(1)-W_(2)) with the maximum permissible error is :

The relative density of a material of a body is found by weighing it f

1.	The relative density of a material of a body is found by weighing it first in air and then in water. If the wt. of the body in air is W_(1)=800+-005newton and weight in water is W_(2)=600+-005 newton. Then the relative density, p_(r)=(W_(1))/(W_(1)-W_(2)) with the maximum permissible error is :
Answer» `400+-062%` `400+-082%` `400+-32%` `400+-562%` Solution :RELATIVE DENSITY, `rho_(r)=(W_(1))/(W_(1)-W_(2))` `=(800)/(800-600)=400` `(Deltarho_(r))/(rho_(r))xx100=(DeltaW_(1))/(W_(1))xx100+(Delta(W_(1)-W_(2)))/(W_(1)-W_(2))xx100` `=(005)/(800)xx100+(005+005)/(2)xx100` `5.62%` `:.rho_(r)=400+-562%` Hence CORRECT choice is `(d)`.

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The relative density of a material of a body is found by weighing it first in air and then in water. If the wt. of the body in air is W_(1)=8*00+-0*05newton and weight in water is W_(2)=6*00+-0*05 newton. Then the relative density, p_(r)=(W_(1))/(W_(1)-W_(2)) with the maximum permissible error is :

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The relative density of a material of a body is found by weighing it first in air and then in water. If the wt. of the body in air is W_(1)=800+-005newton and weight in water is W_(2)=600+-005 newton. Then the relative density, p_(r)=(W_(1))/(W_(1)-W_(2)) with the maximum permissible error is :