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The relative density of material of a body is found by weighting it first in air and then in water . If the weight in air is `( 5.00 +- 0.05) N` and the weight in water is `(4.00 +- 0.05) N`. Find the relative density along with the maximum permissible percentage error.A. `5.0 +- 11%`B. `5.0 +- 1%`C. `5.0 +- 6%`D. `1.25 +- 5%` |
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Answer» Correct Answer - a Weight in air`= (5.00 +- 0.05)N` Weight in water `= (4.00 +- 0.05)N` Loss of weight in water `= (1.00 +- 0.1)N` Now relativedensity `= ("weight in air")/("weight loss in water")` i.e.`R.D= (5.00 +- 0.05)/(1.00 +- 0.1)` Now reletive density with max peemissible error `= (5.00)/(1.00) +- ((0.05)/(5.00) + (0.1)/(1.00)) xxx 100 = 5.0 +- (1 +10)%` `= 5.0 + 11%`. |
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