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The relative lowering of vapour pressure of an aqueous solution containing a non-volatile solute, is 0.0125. The molality of the solution isA. `0.70`B. `0.50`C. `0.90`D. `0.80` |
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Answer» Correct Answer - A `(p^(@)-p_(s))/(p^(@))=x_(2)rArr(p^(@)-p_(s))/(p^(@))=(wN)/(mW)` `0.0125=(wM)/(mW)rArr(w)/(mW)=(0.0125)/(18)=0.00069` `"Hence, molality"=(w)/(mW)xx1000=0.00069xx1000=0.69` `~=0.70` |
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