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The relative magnetic permeability of the medium is 2.5 and the relative electrical permittivity of the medium is 2.25 Compute the refractive index of the medium. |
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Answer» Solution :DIELECTRIC constant ( relative PERMEABILITY of the medium ) is `epsi _(r) =2.25` Magneic permeability is `mu_(r) =2.5` Refractive INDES of the medium , `n= sqrt(epsi _r mu_r) = sqrt( 2.25 xx 2.5) = 2.37` |
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